(4(x^2-9)-8x^2)/(x^2-9)^2

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Solution for (4(x^2-9)-8x^2)/(x^2-9)^2 equation: 


D( x )

(x^2-9)^2 = 0

(x^2-9)^2 = 0

(x^2-9)^2 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

(4*(x^2-9)-(8*x^2))/((x^2-9)^2) = 0

(4*(x^2-9)-8*x^2)/((x^2-9)^2) = 0

4*(x^2-9)-8*x^2 = 0

4*(x^2-9)-8*x^2 = 0

-4*x^2-36 = 0

-4*x^2-36 = 0

(-4*x^2-36)/((x^2-9)^2) = 0

-4*x^2 = 36 // : -4

x^2 = -9

x belongs to the empty set

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